Answer:
Since the ramp is frictionless only the height must be considered
1/2 m v^2 = m g h where h is the height of the ramp
v = (2 g h)^1/2 = (2 * 9.8 * 12)^1/2 = 15.3 m/s
Check:
12 = 1/2 g t^2 for a freely falling object
t = 1.56 sec falling time
V = g t = 9.80 m/s * 1.56 sec = 15.3 m.s