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Trapezoid JKLM with vertices J(-5, 6), K(-3, 5), L(-2, 2), and M(-6, 0): (x, y) = (x + 7, y - 3)

User Lenn
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1 Answer

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To find the coordinates of the trapezoid JKLM after the transformation (x, y) = (x + 7, y - 3), we need to apply this transformation to each vertex of the original trapezoid.

Given the original coordinates of the vertices:

J(-5, 6)

K(-3, 5)

L(-2, 2)

M(-6, 0)

Let's apply the transformation to each vertex:

J' = (-5 + 7, 6 - 3) = (2, 3)

K' = (-3 + 7, 5 - 3) = (4, 2)

L' = (-2 + 7, 2 - 3) = (5, -1)

M' = (-6 + 7, 0 - 3) = (1, -3)

Therefore, after applying the transformation (x, y) = (x + 7, y - 3) to each vertex, the coordinates of the trapezoid JKLM become:

J'(2, 3)

K'(4, 2)

L'(5, -1)

M'(1, -3)

User Alsdkjasdlkja
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