Question

A 7.94 nC charge is located 1.75 m from a 4.18 nC point charge. Find the magnitude of the electrostatic force that one charge exerts on the other.

Answer 1

Step-by-step explanation:

`force \: = \frac{ke * q1 * q2}{ {r}^(2) } \\ force \: = \frac{9 * {10}^(9) * 7.94 * {10}^( - 9) * 4.18 * {10}^( - 9) }{( {1.75}^(2) )} \\`

Force = 97.54 × 10^-9 N