Final answer:
Given [a]=2.3 m [b]=1.5 m k=0.011 m-2s-1, the rate of the reaction is 0.058 M^-2/s^-1.
Step-by-step explanation:
The rate of a reaction can be calculated using the rate law expression.
In this case, the rate law expression is rate = k[A]²
where
[A] is the concentration of reactant A
k is the rate constant.
Using the given information, [A] = 2.3 M and [B] = 1.5 M, and k = 0.011 M-2s-1.
Inserting these values into the rate law expression, we can calculate the rate of the reaction:
rate = k[A]² = (0.011 M-2s-1)(2.3 M)2 = 0.058 M-2s-1
Therefore, the rate of the reaction is 0.058 M-2s-1.