Question

a baseball is projected horizontally with an initial speed of 13.7 m/s from a height of 2.43 m. at what horizontal distance will the ball hit the ground? (neglect air friction.)

Answer 1

9.65 m

Step-by-step explanation:

Given:

`y_o=2.43\ m`

`y = 0`

`v_x=13.7\ m/s`

`v_(oy)=0`

`g=9.8\ m/s^2`

`y = y_o+v_(oy)t-(1)/(2) gt^2`

`0=2.43+0-(1)/(2) (9.8)t^2`

`4.9t^2=2.43`

`t=√(2.43/ 4.9)`

`t=0.704\ s`

`x=x_o+v_xt`

`=0+13.7*0.704`

`=9.65\ m`