Final Answer:
The surface integral of
across the sphere S with center at the origin and radius 2 is

Step-by-step explanation:
To calculate the surface integral using the Divergence Theorem, we first need to find the divergence of
. The divergence
is given by the sum of the partial derivatives of the components of
with respect to their respective variables:
![\[ \\abla \cdot \mathbf{F} = 3x^2 + 3y^2 + 3z^2. \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/tg37vuuuvdm0zzodivw0lxqt4f95y9p3lg.png)
Now, applying the Divergence Theorem, the surface integral of
over the closed surface S is equal to the triple integral of the divergence of
over the region V enclosed by S:
![\[ \iint_S \mathbf{F} \cdot d\mathbf{S} = \iiint_V (\\abla \cdot \mathbf{F}) \, dV. \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/8exf3efklow1ts8i4ohbfis29nt9fq4bt7.png)
For the sphere S with radius r = 2 and center at the origin, the region V can be described in spherical coordinates as
. The triple integral becomes:
![\[ \iiint_V (\\abla \cdot \mathbf{F}) \, dV = \int_0^(2\pi) \int_0^\pi \int_0^2 (3\rho^2) \rho^2 \sin\phi \, d\rho \, d\phi \, d\theta. \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/2ny75z732my33974ksaq23u3eqvxway023.png)
Evaluating this integral gives the final answer of
, which represents the flux of
across the sphere S.
Full Question:
Use the Divergence Theorem to calculate the surface integral S F · dS; that is, calculate the flux of F across S. F(x, y, z) = (x3 + y3)i + (y3 + z3)j + (z3 + x3)k, S is the sphere with center the origin and radius 2.