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How many grams of titanium could be obtained from a 55.00 mole sample of Ti6Al4V

User Timsen
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Answer:

Now, find the molar mass of each element:

The molar mass of titanium (Ti) is approximately 47.87 g/mol.

The molar mass of aluminum (Al) is approximately 26.98 g/mol.

The molar mass of vanadium (V) is approximately 50.94 g/mol.

Next, calculate the molar mass of Ti6Al4V by summing the molar masses of its individual elements:

Molar mass of Ti6Al4V = (6 × Molar mass of Ti) + (4 × Molar mass of Al) + (4 × Molar mass of V)

Molar mass of Ti6Al4V = (6 × 47.87 g/mol) + (4 × 26.98 g/mol) + (4 × 50.94 g/mol)

Molar mass of Ti6Al4V ≈ 287.22 g/mol

Now that you know the molar mass of Ti6Al4V, you can calculate the number of moles in your 55.00 mole sample of Ti6Al4V. Then, you can determine the number of moles of titanium (Ti) in that sample by using the molar ratio of titanium in Ti6Al4V, which is 6 moles of Ti for every mole of Ti6Al4V.

Number of moles of Ti6Al4V = 55.00 moles

Number of moles of Ti = (55.00 moles) × (6 moles Ti6Al4V / 1 mole Ti6Al4V)

Now, calculate the mass of titanium (Ti) in grams:

Mass of Ti = (Number of moles of Ti) × (Molar mass of Ti)

Mass of Ti = [(55.00 moles) × (6 moles Ti6Al4V / 1 mole Ti6Al4V)] × 47.87 g/mol

Mass of Ti ≈ 15389.91 g

So, you can obtain approximately 15,389.91 grams (or about 15.39 kilograms) of titanium from a 55.00 mole sample of Ti6Al4V.

Step-by-step explanation:

To determine how many grams of titanium (Ti) can be obtained from a sample of Ti6Al4V, you need to consider the molar mass of titanium and the molar ratio of titanium in Ti6Al4V.

User Hussein Abdallah
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