Final answer:
In 90 grams of glucose, there are approximately 1.8066*10^24 atoms of Carbon, 3.6132*10^24 atoms of Hydrogen, and 1.8066*10^24 atoms of Oxygen.
Step-by-step explanation:
To calculate the number of atoms of each type in 90 grams of glucose C6H12O6, we first need to find the molar mass of glucose. The molar mass of glucose is approximately 180.156 grams per mole (adding up the molar masses of carbon, hydrogen, and oxygen in the formula). Thus in 90 grams of glucose, there are 90/180.156 = 0.5 moles of glucose.
Because there are 6 Carbon atoms, 12 Hydrogen atoms, and 6 Oxygen atoms in one molecule of glucose, in 0.5 moles of glucose, we have 0.5 * 6 = 3 moles of Carbon atoms, 0.5 * 12 = 6 moles of Hydrogen atoms, and 0.5 * 6 = 3 moles of Oxygen atoms. Avogadro's number (approximately 6.022 * 10^23) tells us the number of atoms in a mole, so we multiply the moles of each atom by Avogadro's number to get the number of atoms. Hence, there are about 1.8066*10^24 atoms of Carbon, 3.6132*10^24 atoms of Hydrogen, and 1.8066*10^24 atoms of Oxygen in 90 grams of glucose.
Learn more about Atoms in Glucose