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Explain the formation of the ionic compound MgO with the help of Lewis electron dot structure. a) True b) False

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Answer:

False.

Step-by-step explanation:

b) False. The formation of the ionic compound MgO can be explained using the Lewis electron dot structure. In the Lewis structure, magnesium (Mg) would have a valence electron configuration of 2 electrons in its outer shell, while oxygen (O) would have 6 electrons in its outer shell.

To form an ionic compound, magnesium will lose its two valence electrons to achieve a stable, full shell configuration. Oxygen will gain these two electrons to also achieve a stable configuration. This leads to the formation of Mg2+ cation and O2- anion.

The Lewis structure of MgO will show the transfer of electrons, with Mg donating two electrons to O, resulting in an ionic bond. The structure can be depicted as Mg^2+ [O]^2-. The positively charged magnesium ion and the negatively charged oxygen ion are held together by the electrostatic force of attraction, forming the ionic compound magnesium oxide (MgO).

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