Question

A stream of humid air containing 1.00 mole% H2O(v) and the balance dry air is to be humidified to a water content of 10.0 mole% H2O(v). For this purpose, liquid water is fed through a flow meter and evaporated into the air stream. The flow meter reading, r, is 95. The only available calibration data for the flow meter are two points, indicating that readings of r=15 and r=50 correspond to flow rates v'=40.0 ft3/h and v'=96.9 ft3/h, respectively. Estimate the molar flow rate (lbmole/h) of the humidified air solution.

Answer 1

By setting up a proportion based on the given data points, we can calculate the molar flow rate of the humidified air solution to be 154.375 lbmole/h.

Step-by-step explanation:

To estimate the molar flow rate of the humidified air solution, we need to use the calibration data for the flow meter. The calibration data states that a flow meter reading of r=15 corresponds to a flow rate of v'=40.0 ft3/h, and a flow meter reading of r=50 corresponds to a flow rate of v'=96.9 ft3/h. We can use these data points to calculate the molar flow rate of the humidified air solution by setting up a proportion.

First, we calculate the difference in flow meter readings: 50-15 = 35.
Then, we calculate the difference in flow rates: 96.9-40.0 = 56.9.
Next, we calculate the flow rate per flow meter reading: 56.9/35 = 1.625.
Finally, we can use the flow rate per flow meter reading to calculate the molar flow rate of the humidified air solution:
molar flow rate = 1.625 * 95 = 154.375 lbmole/h.