Answer:
Mole of NaOH = 0.00308 mole
Step-by-step explanation:
From the question given above, the following data were obtained:
Volume = 22 mL
Molarity = 0.140 M
Mole of NaOH =?
Next, we shall convert 22 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
22 mL = 22 mL × 1 L / 1000 mL
22 mL = 0.022 L
Finally, we shall determine the number of mole of NaOH in the solution. This can be obtained as shown below:
Volume = 0.022 L
Molarity = 0.140 M
Mole of NaOH =?
Molarity = mole / Volume
0.140 = Mole of NaOH / 0.022
Cross multiply
Mole of NaOH = 0.140 × 0.022
Mole of NaOH = 0.00308 mole
Thus, 0.00308 mole of NaOH is present in the solution.