Answer:
The 1.5V battery can power the flashlight bulb drawing 0.60A for 83.33 minutes before it is depleted.
Step-by-step explanation:
To determine how long a 1.5V battery can power a flashlight bulb drawing 0.60A, you can use the formula for calculating the energy (in joules) consumed by an electrical device over time:
Energy (Joules) = Power (Watts) × Time (Seconds)
In this case, the power (P) is given by the product of the voltage (V) and current (I):
Power (Watts) = Voltage (Volts) × Current (Amperes)
So, first, calculate the power consumption of the flashlight bulb:
Power (Watts) = 1.5V × 0.60A = 0.90 Watts
Now, you want to find out how long the battery can power the bulb, so rearrange the energy formula to solve for time:
Time (Seconds) = Energy (Joules) / Power (Watts)
Given that the battery stores 4.5 kJ (kilojoules), which is equivalent to 4,500 joules, and the power consumption is 0.90 watts:
Time (Seconds) = 4,500 J / 0.90 W = 5,000 seconds
Now, to express the time in more practical units, convert seconds to minutes:
Time (Minutes) = 5,000 seconds / 60 seconds/minute ≈ 83.33 minutes
So, the 1.5V battery can power the flashlight bulb drawing 0.60A for approximately 83.33 minutes before it is depleted.