Question

Iridium has two naturally occurring isotopes, 191Ir and 193Ir. State the number of protons, neutrons, and electrons in an 191Ir atom.

Answer 1

An iridium atom with a mass number of 191 has 77 protons, 77 electrons, and 114 neutrons.

Step-by-step explanation:

The question involves iridium, which is a chemical element with the symbol Ir. An iridium atom with a mass number of 191, denoted as 191Ir, has 77 protons, given that iridium's atomic number (Z) is 77. Since atomic number also represents the number of electrons in a neutral atom, 191Ir also has 77 electrons. To find the number of neutrons, we use the mass number (A) which is 191. The number of neutrons (N) is the difference between the mass number and the number of protons: N = A - Z, so for 191Ir, it is 191 - 77 = 114 neutrons.