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Subtract y² - 3y - 4 from the sum of 4y ²- 2y + 3, - 3y² + 6 and - 5y² + 6y

User Estela
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Final answer:

To subtract y² - 3y - 4 from the given expression, first find the sum of the three terms. Then, subtract the first term from the sum. The final result is -5y² + 9y + 13.

Step-by-step explanation:

To subtract y² - 3y - 4 from the sum of 4y ²- 2y + 3, - 3y² + 6, and - 5y² + 6y, we need to first find the sum of the three terms. Then, we will subtract the first term from the sum.

Sum of the three terms: (4y² - 2y + 3) + (- 3y² + 6) + (- 5y² + 6y)

Simplify the expression: 4y² - 3y² - 5y² - 2y + 6 + 6y + 3

Combine like terms: (4 - 3 - 5)y² + (-2 + 6y) + (6 + 3)

-4y² + 6y + 9

Now we subtract the first term y² - 3y - 4 from the sum:

(-4y² + 6y + 9) - (y² - 3y - 4)

Distribute the negative sign: -4y² + 6y + 9 - y² + 3y + 4

Combine like terms: (-4 - 1)y² + (6 + 3)y + (9 + 4)

-5y² + 9y + 13

Learn more about Subtracting Polynomials

User Sachin Shanbhag
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