Final answer:
To subtract y² - 3y - 4 from the given expression, first find the sum of the three terms. Then, subtract the first term from the sum. The final result is -5y² + 9y + 13.
Step-by-step explanation:
To subtract y² - 3y - 4 from the sum of 4y ²- 2y + 3, - 3y² + 6, and - 5y² + 6y, we need to first find the sum of the three terms. Then, we will subtract the first term from the sum.
Sum of the three terms: (4y² - 2y + 3) + (- 3y² + 6) + (- 5y² + 6y)
Simplify the expression: 4y² - 3y² - 5y² - 2y + 6 + 6y + 3
Combine like terms: (4 - 3 - 5)y² + (-2 + 6y) + (6 + 3)
-4y² + 6y + 9
Now we subtract the first term y² - 3y - 4 from the sum:
(-4y² + 6y + 9) - (y² - 3y - 4)
Distribute the negative sign: -4y² + 6y + 9 - y² + 3y + 4
Combine like terms: (-4 - 1)y² + (6 + 3)y + (9 + 4)
-5y² + 9y + 13
Learn more about Subtracting Polynomials