Question

What tension must a 40.8 cm length of string support in order to whirl an attached 1000.0 g stone in a circular path at 3.29 m/s?

Answer 1

26.53 N

Step-by-step explanation:

r = 40.8 cm = 0.408 m

m = 1000.0 g = 1 kg

v = 3.29 m/s

`F_s=ma_s`

`=m(v^2)/(r)`

`=1*(3.29^2)/(0.408)`

`=26.53\ N`