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What tension must a 40.8 cm length of string support in order to whirl an attached 1000.0 g stone in a circular path at 3.29 m/s?

User ColinE
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1 Answer

4 votes

Answer:

26.53 N

Step-by-step explanation:

r = 40.8 cm = 0.408 m

m = 1000.0 g = 1 kg

v = 3.29 m/s


F_s=ma_s


=m(v^2)/(r)


=1*(3.29^2)/(0.408)


=26.53\ N

User Hop
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7.5k points