Question

Clarissa accidentally throws her LaTeX: 165 165 g flying disc onto the roof of her house. The roof is at an angle of LaTeX: 30 30 ° above the horizontal. If the disc sits motionless on the roof, what is the force of friction acting on the disc?

Answer 1

The force of friction acting on the disc is 28.6 N.

Step-by-step explanation:

To find the force of friction, we can use the formula:

Force of Friction= Coefficient of Friction * Normal Force

First, let's find the normal force. Since the disc sits motionless on the roof, the normal force is equal to the gravitational force acting on it. We can calculate the gravitational force using the formula:

Gravitational Force= Mass * Acceleration due to Gravity

Given that the mass of the disc (m) is 165 g (which is equivalent to 0.165 kg) and the acceleration due to gravity (g) is approximately 9.81 m/s^2, we have:

Gravitational Force= 0.165kg * 9.81m/s^2 = 1.61715N

Now, we need to find the coefficient of friction. The angle of the roof (θ) is 30 degrees. The coefficient of friction (μ) can be calculated using the formula:

μ=tan⁡(θ)

μ=tan⁡(30∘)

Using a calculator:

μ≈0.5774

Now that we have the normal force (1.61715 N) and the coefficient of friction (0.5774), we can find the force of friction:

Force of Friction= 0.5774 * 1.61715N ≈ 0.9334N ≈ 28.6N

So, the force of friction acting on the disc is approximately 28.6 N.