Answer: 2.24 m/s
Step-by-step explanation:
Let's use kinetic energy equations to solve this problem:
The kinetic energy of the first vehicle before the collision is:
Ek=½mv^2 = ½ * 450 kg * 16 m/s^2 = 4,800 J
The kinetic energy of the second vehicle is equal to that of the first, because the collision has made them come to a complete standstill:
Ek = ½mv^2 = ½ * 400 kg * v^2 = 4,800 J
From this, we get that:
v = sqrt(4,800 J / 400 kg) = sqrt(4.8) m/s = 2.24 m/s
So the second vehicle was travelling at 2.24 m/s before the collision.