Question

3. Study the circuit diagram below and answer the questions that follow. The four resistors are identical. As A₂ 33 V/₁₂ V₂ V₂ A3 V5 3.1 What would be the readings on the following if V5 was reading 6 V? 3.1.1 V2 3.1.2 V3 3.2 What would be the readings on the following if A1 was reading 3 A? 3.2.1 A2 3.2.2 A3​

Answer 1

Step-by-step explanation:

3.1.1 V2:

R1 and R2 are connected in parallel, and since they are identical, their voltage drops will be the same. Since V2 is in series with R2, R2's voltage drop across it will be V1 minus V2. Since V1 is 33 V and V2 is 6 V, R2's voltage drop is 33-6=27 V. Since R1 is in parallel with R2, it will also have a voltage drop of 27 V across it. Therefore, V2 will be reading 27 V.

3.1.2 V3:

R3 and R4 are in series, so their voltage drops will be the same. Since E3 is in parallel with R4, it will see an effective resistance of (R+R4)/(R+R4+R3) + (R4//R3)/(R+R4+R3)= (R4+R3)/(R+R4+R3) + (R4//R3)/(R+R4+R3)= 6.00Ω. Since E4 is in series with it, V3 will be = (E3)((R+R4)/(R+R4+R3) + (R4//R3)/(R+R4+R3)) = (E3)(1.5) = 4.5 V.

3.2.1 A2:

Since A2 is in series with R2, its current will be = V2/R2 = 6/10 = 0.6 A. Since A3 is in series with R3, its current will be = V3/R3 = 4.5/10 = 0.45 A. The total current through R1 is I = (A2+A3)/(2/3)=0.6+0.45=1.05 A.

3.2.2 A3:

A3 is in series with R3, so its current will be = V3/R3 = 4.5/5 = 0.9 A.