Question

A mechanic works on a overhaul of a transmission.he starts at 8.25 am and finishes at 4:23pm,and takes one hour off for lunch.at 18.75 per hour,how much did the mechanic earn

Answer 1

1. The mechanic started at 8:25 am and finished at 4:23 pm. This is a total of 7 hours and 58 minutes of work (4:23 pm - 8:25 am).

2. The mechanic also took one hour off for lunch, so we subtract that hour from the total hours worked: 7 hours and 58 minutes - 1 hour = 6 hours and 58 minutes of work.

3. Convert the minutes to decimal form for calculation. There are 60 minutes in an hour, so 58 minutes is 58/60 = 0.967 hours.

4. Add the decimal minutes to the total hours: 6 hours + 0.967 hours = 6.967 hours.

5. Now, multiply the total hours worked by the hourly rate: 6.967 hours * $18.75/hour = $130.83.

So, the mechanic earned $130.83 for the overhaul of the transmission.