38.8k views
4 votes
A mechanic works on a overhaul of a transmission.he starts at 8.25 am and finishes at 4:23pm,and takes one hour off for lunch.at 18.75 per hour,how much did the mechanic earn

1 Answer

7 votes
1. The mechanic started at 8:25 am and finished at 4:23 pm. This is a total of 7 hours and 58 minutes of work (4:23 pm - 8:25 am).

2. The mechanic also took one hour off for lunch, so we subtract that hour from the total hours worked: 7 hours and 58 minutes - 1 hour = 6 hours and 58 minutes of work.

3. Convert the minutes to decimal form for calculation. There are 60 minutes in an hour, so 58 minutes is 58/60 = 0.967 hours.

4. Add the decimal minutes to the total hours: 6 hours + 0.967 hours = 6.967 hours.

5. Now, multiply the total hours worked by the hourly rate: 6.967 hours * $18.75/hour = $130.83.

So, the mechanic earned $130.83 for the overhaul of the transmission.
User Chee
by
8.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories