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Graph of the linear equation 2x+3y=15 and 4x+6y=24

User Ndm
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Final answer:

To graph the given linear equations, convert them to slope-intercept form, plot the y-intercept and use the slope to find additional points on the line.

Step-by-step explanation:

To graph the linear equations 2x+3y=15 and 4x+6y=24, we can start by converting each equation to slope-intercept form, y=mx+b.

For the first equation, we have:
2x + 3y = 15
3y = -2x + 15
y = (-2/3)x + 5

For the second equation, we have:
4x + 6y = 24
6y = -4x + 24
y = (-4/6)x + 4

Now we can graph the equations using their slopes and y-intercepts. The first equation has a slope of -2/3 and a y-intercept of 5, while the second equation has a slope of -4/6 and a y-intercept of 4. Plotting these points on a graph will give us the lines corresponding to each equation.

Learn more about Graphing linear equations

User Galian
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