Question

A nurse mixes 60 cc of a 70% saline solution with a 10% saline solution to produce a 34% saline solution. How much of the 10% solution should he use? The amount of 10% saline solution needed is CC.

Answer 1

To find the amount of 10% saline solution needed to mix with a 70% saline solution to obtain a 34% saline solution, an equation based on the total amount of pure saline in the original and final solutions can be set up and solved.

Step-by-step explanation:

To solve this problem, we can use the concept of mixtures and solutions. The main strategy is to set up an equation that represents the total amount of pure saline in your initial solutions and in your final solution. The equation would look like this: amount of saline in Solution1 + amount of saline in Solution2 = total saline in the mixture.

If we denote the unknown quantity of the 10% saline solution as 'x', we can describe the amount of pure saline in each solution like this:

• For the 70% saline solution: 0.70 * 60 cc = 42 cc
• For the 10% saline solution: 0.10 * x cc

The resultant solution is a 34% saline solution, and its total volume in cc is the sum of the volumes of the initial solutions, which is 60cc + x. Therefore, the amount of pure saline in the mix is: 0.34 * (60 + x) cc.

From this, we now build our equation: 42cc (from the 70% solution) + 0.10x (from the 10% solution) = 0.34 * (60 + x).

Solving this equation gives us the value of x, which represents the volume in cc of the 10% solution needed to get a 34% solution when mixed with 60 cc of a 70% saline solution.

Learn more about Mixtures and Solutions