Question

Please help. I can’t get the scanner to subtract it. Thanks.

Answer 1

`-x^(2) + 8x - 12 = 0`

Explanation:

Why use a scanner? You should learn how to do this, and this is a simple one: just subtract everything inside the 2nd parentheses. Be careful with signs!

`(3x^(2) + 2x -9) - 4x^(2) + 6x - 3`

Remember that "subtracting a negative gives a positive"? That's why 6x is positive. Now just remove the 1st set of parentheses:

`3x^(2) + 2x - 9 - 4x^(2) +6x - 3`

Now "group like terms," which just means to put the x-squareds and the x's and the numbers together:

`(3x^(2) - 4x^(2)) + (2x + 6x) + (-9 - 3)` Simplify to:

`-x^(2) + 8x - 12 = 0`

Not so hard, was it? I added "= 0" to put it in the standard form:

`ax^(2) + bx + c = 0`