Question

The area of a baseball field bounded by home plate, first base, second base, and third base is a square. If a player at first base throws the ball to a player at third base, what is the distance the player has to throw? A. 16200 ftB. square rout of 180 ftC. square rout of 16200 ftD. 180 ft

Answer 1

There is 90 feet between the bases in a baseball infield. By the Pythagorean theorem the diagonal of a baseball infield is

(90^2 + 90^2)^1/2 = 16200^1/2 = 127.3 ft

Note- this also the distance that a catcher must throw in trying to throw out a runner stealing second base.