To find the values of a and b, we need to compare the expanded expression on the left side of the equation to the right side. The value of a+b is 3k+4.
To find the values of a and b, we need to expand the expression on the left side of the equation and compare it to the right side of the equation. Multiplying (3y-1)(2y+k) using the distributive property gives us 6y^2+ (3yk-2y+k). Equating this to ay^2 + by - 5, we can identify the coefficients of y^2, y, and the constant term on both sides. Comparing the coefficients, we get a=6, b=3k-2, and -5=k.
Therefore, the value of a+b is 6 + (3k-2). Simplifying, we get a+b = 3k+4.
Learn more about Expanding Expressions