Answer:
12.8 pounds of aluminum would occupy approximately 2.1506616 liters.
Step-by-step explanation:
To determine the number of liters that 12.8 pounds of aluminum would occupy, we need to convert the weight from pounds to grams and then use the density of aluminum.
First, let's convert the weight from pounds to grams:
1 pound is approximately equal to 453.592 grams.
Therefore, 12.8 pounds of aluminum is equal to:
12.8 pounds * 453.592 grams/pound = 5816.8576 grams
Now, let's calculate the volume in liters using the density of aluminum:
Density of aluminum = 2.7 grams/ml
Volume (in milliliters) = Mass (in grams) / Density (in grams/ml)
Volume = 5816.8576 grams / 2.7 grams/ml = 2150.6616 ml
Finally, let's convert the volume from milliliters to liters:
1 liter is equal to 1000 milliliters.
Volume (in liters) = 2150.6616 ml / 1000 = 2.1506616 liters