Question

Given the first term (a1) is 4 and the common difference (d) is 6, find the 10th term (an) of the arithmetic sequence.

Answer 1

a₁₀ = 58

Explanation:

the nth term of an arithmetic sequence is

`a_(n)` = a₁ + d(n - 1)

a₁ is the first term , d the common difference and n the term number

given a₁ = 4 and d = 6

substitute these values into the nth term formula

a₁₀ = 4 + 6(9) = 4 + 54 = 58