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Find the line perpendicular to y = 3x - 8 that includes the point (6, 1)

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Answer: y = -x/3 +3 is the line perpendicular to the line y = 3x -8

Explanation:

y = 3x -8 is our given line

To find the perpendicular line, we need to find the slope.

Slope = m = negative reciprocal of 3

m = -1/3

Through (6,1)

y - 1 = (-1/3)(x -6)

y-1= -x/3 +2

y = -x/3 +3 is our perpendicular line...


From MysticAlanCheng

User Nikhil Surendran
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