Question

A molten sample of 1.00kg of iron with a specific heat of 0.385J/g.K at 1000.K is immersed in a sample of water. If the water absorbs 270 kJ of heat what is the final temperature of the iron?

Answer 1

Final T = 298.7K

Step-by-step explanation:

In this problem, the heat given for the iron is equal to the heat that water absorbs. Using the equation:

Q = C*m*ΔT

Where Q is heat given = 270000J

C is specific heat of substance = 0.385J/gK

m is mass of iron = 1000g

ΔT is change in temperature = Initial temperature - Final temperature.

270000J = 0.385J/gK*1000g*(1000K-Final temperature)

701.3J/K = 1000K - Final T

Final T = 298.7K