CO has a molar mass of 44.01 g/mol, which means that 1 mole of CO weighs 44.01 grams.
We want to convert 14.35 grams of ethanol to acetic acid, so we need to know how many moles of ethanol there are. Let's first multiply the given mass of ethanol by its molar mass:
14.35 (g) x 32.06 (g/mol) = 45.85 mol
So, we have 45.85 moles of methanol. If methanol reacts with CO to produce acetic acid, we need to know how many moles of CO we need to use, based on the stoichiometry of the reaction. The reaction equation gives us a 2:1 ratio for CO and methanol:
2 CH₃OH(l) + CO(g) → CH₃CO₂H(aq)
So, for every mole of CH₃OH we react, we will need 0.5 mole of CO. Therefore, we need 23.92 moles of CO to convert all the methanol to acetic acid.
Using the mass of 1 mole of CO, we can convert moles of CO to grams:
23.92 (mol) x 44.01 (g/mol) = 1050.93 (g)
So, we need 1051 grams of CO to completely convert 14.35 grams of methanol to acetic acid.