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determine the heat of vaporization of nitrogen 65k 130.5torr 70k 289.5torr 75k 570.8torr 80k 1028torr 85k 1718torr

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To determine the heat of vaporization of nitrogen, we can use the Clausius-Clapeyron equation:

ln(P2/P1) = -(ΔHvap/R)(1/T2 - 1/T1)

Where:
P1 and P2 are the initial and final pressures, respectively.
T1 and T2 are the initial and final temperatures, respectively.
ΔHvap is the heat of vaporization we want to calculate.
R is the gas constant (8.314 J/(mol·K)).

Let's calculate the heat of vaporization (ΔHvap) using the given data:

P1 = 130.5 torr
T1 = 65 K
P2 = 289.5 torr
T2 = 70 K

First, convert the pressures from torr to atm:
P1 = 130.5 torr / 760 torr/atm
P2 = 289.5 torr / 760 torr/atm

Substitute these values into the equation:
ln(P2/P1) = -(ΔHvap/R)(1/T2 - 1/T1)

Solve for ΔHvap:
ΔHvap = -(R * (ln(P2/P1))/(1/T2 - 1/T1))

Repeat this process for each set of data to calculate the heat of vaporization at different temperatures and pressures.

Remember to convert all temperatures to Kelvin before performing any calculations.
User Harel Gliksman
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