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Solve 2x + 8 < 10 or 2x + 8 > 20.

0 0 0
A. x < 2 or a > 6
Ο B. x < 1 or a > 2
C. x < 2 and a > 2
Ο D. x < 1 or a > 6

User Antonyoni
by
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1 Answer

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Answer: B. x < 1 or a > 2.

First, let's solve the first inequality, 2x + 8 < 10:

Subtract 8 from both sides:

2x + 8 - 8 < 10 - 8

2x < 2

Divide both sides by 2:

(2x)/2 < 2/2

x < 1

Now, let's solve the second inequality, 2x + 8 > 20:

Subtract 8 from both sides:

2x + 8 - 8 > 20 - 8

2x > 12

Divide both sides by 2:

(2x)/2 > 12/2

x > 6

User Puneet Verma
by
8.3k points

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