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31 votes
Một điện tích q = 6.10-6 C đặt tại tâm của một hình lập phương. Tính thông lượng điện trường gửi qua mỗi mặt hình lập phương.

b. Một điện tích q = 4.10-8 C đặt tại tâm của một hình vuông. Tính thông lượng điện trường gửi qua mỗi mặt của hình vuông.

User Greg Nisbet
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2 Answers

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12 votes

Answer:

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User Siukurnin
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2.7k points
11 votes
11 votes

Final answer:

To calculate the electric flux through each face of a cube with a charge q = 6.10-6 C at its center, we need to use Gauss's law. The electric flux through each face is equal to the electric field strength multiplied by the surface area of the face. In this case, since the cube is symmetrical, the electric flux through each face will be the same.

Step-by-step explanation:

To calculate the electric flux through each face of a cube with a charge q = 6.10-6 C at its center, we need to use Gauss's law. The electric flux through each face is equal to the electric field strength multiplied by the surface area of the face. In this case, since the cube is symmetrical, the electric flux through each face will be the same.

Given:

  • Charge, q = 6.10-6 C
  • Edge length of the cube, a

To find the electric flux, we need to calculate the electric field strength (E). The electric field strength at a point due to a point charge is given by the equation:

E = k * q / r^2

Where:

  • k = Coulomb's constant = 8.99 * 10^9 N*m^2/C^2
  • q = Charge
  • r = Distance from the charge

Using this equation, we can find the electric flux through each face of the cube by calculating the electric field strength at each face and multiplying it by the surface area of the face.

User MEX
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