Question

a car moves at 12m/s and coasts up a hill with a uniform acceleration of -1.6m/s^2. What is the displacement after 6.0s?

Answer 1

43 m

Step-by-step explanation:

Given:

u = 12 m/s

a = -1.6 m/s²

t = 6.0 s

Find: s

s = u t + ½ a t²

s = (12) (6.0) + ½ (-1.6) (6.0)²

s = 43.2

Rounded to two significant figures, the displacement is 43 m.