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Multiply and simplify the following complex numbers: (2-2i)*(4-4i) I need an explanation too please!!!

1 Answer

5 votes

Answer: -16i

Work Shown

(2-2i)*(4-4i)

= 2*(4-4i)-2i(4-4i)

= 2*4+2*(-4i)-2i*4-2i(-4i)

= 8-8i-8i+8i^2

= 8-8i-8i+8(-1)

= 8-8i-8i-8

= 0-16i

= -16i

Therefore, (2-2i)*(4-4i) = -16i where i = sqrt(-1) and i^2 = -1

I used the distributive property on the 1st and 2nd steps.

User Afzaal Ahmad
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