Question

A line includes the points (0, 2) and (1, 6). What is its equation in slope-intercept form?

Answer 1

m = (y2 - y1) / (x2 - x1)

m = (6 - 2) / (1 - 0)

m = 4 / 1

m = 4.

you have the slope (m), you can use one of the points, such as (0, 2), to find the y-intercept (b). Plug the values of the point and the slope into the slope-intercept equation:

2 = 4(0) + b

Since 4(0) is 0, you can simplify:b=2

Now that you have both the slope (m) and the y-intercept (b), you can write the equation of the line in slope-intercept form:

y = mx + b

y = 4x + 2.

So, the equation of the line passing through the points (0, 2) and (1, 6) in slope-intercept form is:

y = 4x + 2.