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El carrusel de la feria del pueblo tiene una velocidad de 2 rpm. En un determinado instante se corta la corriente y como consecuencia del rozamiento, aparece una aceleración de frenado de 0,05 rad/s2.

User Zmf
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1 Answer

8 votes

Answer:

t = 4.19 s, θ = 0.437 rad

Step-by-step explanation:

This is an exercise in rotational kinematics in this case we indicate the angular velocity and the angular acceleration, asking for the time and the angle it takes to stop.

w = w₀ + α t

w² = w₀² + 2 α θ

when the system stops the angular velocity is zero

0 = w₀- α t

0 = w₀² - 2 α θ

t = w₀ / α

tea = w₀² / 2 α

let's reduce the magnitudes to the SI system

w₀ = 2 rpm (2π rad / 1 rev) (1 min / 60s) = 0.209 rad / s

let's calculate

t = 0.209 / 0.05

t = 4.19 s

θ = 0.209 2/2 0.05

θ = 0.437 rad

User Brett Caswell
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