Final answer:
In a cross of AB Hh x AB Hh, the proportion of individuals who will have the Bombay phenotype is 25% because these individuals are homozygous recessive for the H gene.
Step-by-step explanation:
The Bombay phenotype is due to homozygous recessive condition of the H gene. If we cross two organisms with the Hh genotype, we will apply the Punnett square method for determining the offspring phenotypes. Here, we look at the expression of the H gene. As Bombay phenotype is seen in hh genotype, we will potentially see this condition in 25% of the offspring because statistically, a cross between two heterozygotes (Hh x Hh) results in 25% of the offspring being homozygous recessive (hh).
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