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There are 26 cards in a hat, each of them containing a letter of the alphabet. If one card is chosen at random, what is the probability that it is not among the letters H through J, inclusive?

Write your answer in fraction form. Reduce the fraction if necessary.

User Dennis K
by
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1 Answer

2 votes

Answer:

P (desired letters) = 23/26

Explanation:

total cards = 26

letters not required = {H, I, J} = 3

desired letters = 26 - 3 = 23

P(desired letters) = 23/26

User Saffsd
by
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