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Find the slope of the tangent line to the graph of f at the given point. f(x) = x² + 11x - 15 at (1, -3).

User Rjbeckwith
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1 Answer

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Answer: slope is 13

Explanation:

f(x) = x² + 11x - 15 at (1, -3).

f '(1) is what we want

f '(x) = 2x + 11

f '(1) = 2 + 11 = 13 slope is 13

User Yahwe Raj
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