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Use the definition of the derivative to compute f'(c) for the given function. Use the results to determine an equation for the line tangent to the graph of f(x) at x = c. f(x) = x² + 3x; c = 4

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Answer: tangent line equation is y = 11x - 16 with f '(4) = 11

Explanation:

function f(x) = x² + 3x;

we want f ' (c) ?

c = 4

f '(x) = 2x + 3

f '(4) = 2*4 + 3 = 8 + 3 = 11

f '(4) = 11 slope is 11

y - f(4) = 11* (x - 4)

y - 28 = 11*(x - 4)

y = 11x - 44 + 28

y = 11x - 16

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