Answer: tangent line equation is y = 11x - 16 with f '(4) = 11
Explanation:
function f(x) = x² + 3x;
we want f ' (c) ?
c = 4
f '(x) = 2x + 3
f '(4) = 2*4 + 3 = 8 + 3 = 11
f '(4) = 11 slope is 11
y - f(4) = 11* (x - 4)
y - 28 = 11*(x - 4)
y = 11x - 44 + 28
y = 11x - 16