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Suppose a driver from Canada, going SW on I-95 crosses into the United States. He travels from New York City to Washington, DC

He drove 366,800 m, and took him 16,440 s. What was his average velocity for the trip in mi/hr?

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Answer:

The driver's average velocity for the trip from New York City to Washington, DC, is approximately 49.96 mi/hr.

Step-by-step explanation:

To find the driver's average velocity for the trip from New York City to Washington, DC in mi/hr, you can follow these steps:

Convert the distance from meters (m) to miles (mi). 1 mile is approximately 1609.34 meters.

Distance in miles = 366,800 meters / 1609.34 meters/mile ≈ 228.06 miles

Convert the time from seconds (s) to hours (hr). There are 3600 seconds in 1 hour.

Time in hours = 16,440 seconds / 3600 seconds/hour ≈ 4.567 hours

Calculate average velocity using the formula:

Average Velocity (in mi/hr) = Distance (in miles) / Time (in hours)

Average Velocity = 228.06 miles / 4.567 hours ≈ 49.96 mi/hr

Thus, 49.96 mi/hr.

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