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A boat decreases its speed from 30 m/s to 18 m/s while traveling a distance of 320 m. What is the acceleration of the boat?

User Kognos
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1 Answer

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Answer: a= .41 m/s²

Step-by-step explanation:

Given:

initial velocity (V₀): 30 m/s

final velocity(Vₓ): 18 m/s

total distance (ΔS): 320m

Need:

Acceleration (a): ?m/s²

to solve this you need to use the kinematics formula:

(Vₓ)² = (V₀)² +2*a*ΔS

Plug in the numbers and solve algebraically for a


(30m/s)^2 = (18m/s)^2 + 2 * a * 320m\\\\ 900 m^2 /s^2 = 324 m^2/s^2 + 640m *a \\-324 m^2/s^2\\\\ 240 m^2/s^2 = 640m *a \\(240 m^2/s^2)/(640m) = a\\\\ a= .406 m/s^2

Round to sigfigs

a= .41 m/s²

User PrimaryChicken
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