Answer:
0.96856
Explanation:
Given info:
μ = 621
σ = 102
Find: P(X < 811)
First, find the z-score:
z = (x - μ)/σ
z = (811 - 621)/102
z = 1.86
Since z = 1.86, this means x is 1.86 standard deviations from the mean. With this information, we can use a standard normal table to find the probability that a randomly selected 32-year-old mortgage applicant has a credit score lower than 811.
Using the standard normal table, we get a probability of 0.96856
Alternatively, we can get the same answer using software. Note: The answer is slightly different due to rounding.