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Find k so that the line containing the points ​(​-3,k) and ​(6​10,​) is parallel to the line containing the points ​(5​,5​) and ​(1​,-2​).

User Gustyn
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1 Answer

1 vote

Answer:

The value of k is 5.75

Explanation:

To find the value of k such that the line containing the points (-3, k) and (6, 10) is parallel to the line containing the points (5, 5) and (1, -2), you can start by determining the slope of the line passing through (5, 5) and (1, -2).

The slope (m) of a line passing through two points (x₁, y₁) and (x₂, y₂) is given by:

m = (y₂ - y₁) / (x₂ - x₁)

For the line passing through (5, 5) and (1, -2):

m = (-2 - 5) / (1 - 5)

m = (-7) / (-4)

m = 7/4

Now, since the line you want to find is parallel to this line, it must also have the same slope. So, the slope of the line passing through (-3, k) and (6, 10) is also 7/4. We can now use this information to find k:

m = (10 - k) / (6 - (-3))

7/4 = (10 - k) / 9

Now, cross-multiply:

7 * 9 = 4 * (10 - k)

63 = 40 - 4k

Add 4k to both sides:

63 + 4k = 40

Subtract 40 from both sides:

4k = 63 - 40

4k = 23

Now, divide by 4:

k = 23 / 4

k = 5.75

So, the value of k is 5.75. The line containing the points (-3, 5.75) and (6, 10) will be parallel to the line containing the points (5, 5) and (1, -2).

User Antfish
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