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a particle travels in a circle of radius 13.2 m at a constant speed of 20 m/s what is the magnitude of the acceleration

User Ozge
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1 Answer

5 votes

Answer:

30.3 m/s²

Step-by-step explanation:

Acceleration = (final velocity - initial velocity) ÷ time

The final velocity is 20 m/s and the initial is 0 m/s

20 - 0 = 20

Next we find the time taken

speed = distance ÷ time

Time = distance ÷ speed

Time = 13.2 ÷ 20

= 0.66

Acceleration = 20 ÷ 0.66

= 30.3

User Mike Petrichenko
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