Question

From the sum of 2y2+3yz,-y2-yz-z2 and yz+2z2, subtract the sum of 3y2-z2 and -y2+yz+z2

Answer 1

To subtract the given expressions, group like terms together, then subtract. The result is -2y^2 + 3yz + z^2.

Step-by-step explanation:

To subtract the sum of the given expressions, simply combine like terms.

1. 2y2 + (-y2) + 3yz +(-yz) + yz = y2 + 3yz
2. -y2 + y2 + (-yz) + yz + z2 + (-z2) = 0
3. yz + (-yz) + 2z2 + (-z2) = z2

Now, subtract the second sum from the first sum:

(y2 + 3yz) - (3y2 - z2)

Combine like terms to simplify the expression:

y2 + 3yz - 3y2 + z2

= -2y2 + 3yz + z2

Learn more about Subtracting Polynomials