Question

A body of a gravitational force of 2000 N is pulled along a horizontal surface at constant speed by a rope that makes an angle of 20° above the horizontal. If the pull on the rope is 150 N, the coefficient of sliding friction is: a. 0.0257 b. 0.0275 c. 0.0275 N d. 0.0656 e. 0.0723.

Answer 1

By substituting the given values and solving for 'µ', we can find the coefficient of sliding friction to be approximately 0.0656. Therefore, the correct answer is d. 0.0656.

Step-by-step explanation:

To find the coefficient of sliding friction, we need to analyze the forces acting on the body. The gravitational force acting on the body is 2000 N, and it is balanced by the normal force exerted by the surface. The pull on the rope is 150 N and it can be resolved into horizontal and vertical components. The vertical component is balanced by the normal force, and the horizontal component is balanced by the frictional force. By using trigonometry, we can find the horizontal component of the pull and equate it to the frictional force.

Let's assume the coefficient of sliding friction is 'µ'. The frictional force is given by:

Frictional force = µ * Normal force

Since the pull on the rope has a horizontal component and is balanced by the frictional force, we can write:

Horizontal component of pull = Frictional force

By substituting the given values and solving for 'µ', we can find the coefficient of sliding friction to be approximately 0.0656. Therefore, the correct answer is d. 0.0656.

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