Question

the equation (x+1)^2 -10(x+1) +16= 0 is a quadratic. To solve the equation we set W= ___. The resulting quadratic equation is ___

Answer 1

(x+1)^2 -10(x+1) +16= 0

x²+2x+1-10x-10+16=0

x²-8x+7=0

b²-4ac = (-8)²-4(1*7)=36

Δ=36

Δ is strictly positive, the equation x²−8x+7=0 admits two solutions

(-b-√Δ)/2a=(8-6)/2 =1

(-b+√Δ)/2a =(8+6)/2=7

solutions :
`x_(1) =1\\x_(2) =7`

Explanation: