Question

Nichol walks at a constant pace of 1.2 m/s and takes 15 minutes to get to school.

Sakura walks at 1.4 m/s and takes 20 minutes to get to school.
What is the difference between the distances they walked?

Answer 1

The difference between the distances they walked is 600 meters.

Explanation:

Let's calculate the distance traveled by Nichol and Sakura with the following equation:

`d = v*t`

Where:

v: is the speed

t: is the time

The distance traveled by Nichol is:

`d_(n) = 1.2 m/s*15min*(60 s)/(1 min) = 1080 m`

And the distance traveled by Sakura is:

`d_(s) = 1.4 m/s*20 min*(60 s)/(1 min) = 1680 m`

Hence, the difference between the distances they walked is:

`d_(t) = d_(s) - d_(n) = 1680 m - 1080 m = 600 m`

Sakura traveled 600 meters more than Nichol.

Therefore, the difference between the distances they walked is 600 meters.

I hope it helps you!