Answer:
The resistance of the lamp is 441 ohms, which is option B.
Step-by-step explanation:
You can use Ohm's law to calculate the resistance of the lamp. Ohm's law relates voltage (V), current (I), and resistance (R) through the formula:
V = I * R
Where:
V = Voltage (in volts)
I = Current (in amperes)
R = Resistance (in ohms)
In this case, you know the power (P) in watts and the voltage (V):
P = 100.0 watts
V = 210.0 volts
First, you can calculate the current (I) using the formula for power:
P = V * I
Rearrange the formula to solve for I:
I = P / V
I = 100.0 watts / 210.0 volts = 0.4762 amperes (approximately)
Now that you have the current (I), you can use Ohm's law to find the resistance (R):
V = I * R
R = V / I
R = 210.0 volts / 0.4762 amperes ≈ 441.02 ohms
So, the resistance of the lamp is approximately 441 ohms, which is option B.